Question

in the expansion of(2x-1/x)^6, find the constant term​

Answer 1

Answer:

Expand (2x+3)4.

Solution

Using the binomial theorem:

(a+b)4=a4+4a3b+6a2b2+4ab3+b4.

Let a=2x and b=3. Then

(2x+3)4=(2x)4+4(2x)3×3+6(2x)2×32+4(2x)×33+34=16x4+96x3+216x2+216x+81.

Step-by-step explanation: