Question

In the expansion of (2x - 8) (x - 4); find the value of
(1) coefficient of x^3(ii) coefficient of x^2 (iii) constant term

Answer 1

Step-by-step explanation:

(2x-8)(x-4) = 2x^2 -16x +32

it can be also written as

0x^3 +2x^2 -16x+32

so. coefficient of x^3 = 0

coefficient of x^2 = 2

constant term =32

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