In the experiment of electrolysis of water in the lab, why is the gas collected at cathode double the quantity of gas collected at anode?
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During electrolysis of water H2 gas is produced at cathode and O2 gas is produced at anode.
At cathode,
H+ ion takes two electron to convert itself into H2 gas. 2 moles of H+ gives 1 mole of H2.
2H + (aq)+2e-→H2 (g)
At anode,
OH– ion releases two electrons to convert into water and O2. 2 mole OH– gives 0.5 mole O2, i.e why volume of one gas collected at one electron is double of another.
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