In the fermentation of sugar, the concentration is reduced from 0.12M to 0.06M in 10h and to 0.03M in 20h. The order of the reaction is?
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Answer:
Explanation:
Given, Concentration is reduced from 0.12 M to 0.06 M in 10 h.
So, t
1/2
=10h
Conc reduced from 0.12 M to 0.03 M in 20hr.
So, t
3/4
=20h
t
3/4
=2×t
1/2
This is valid only for 1st Order Reaction.
So,Order is 1
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