Math, asked by skazimi1417, 11 months ago

A man borrows Rs 10000 at 5% per annum compound interest . He repays 35% of the sum borrowed at the end of the first year and 42% of the sum borrowed at the end of the second year. How much must he pay at the end of the third year in order to clear the debt ?

Answers

Answered by theamazingmysterio
9
Here’s your answer buddy:

For the first year
P
1

=10,000,R=5%
A
1

=10,000(1+
100
5

)
=10000×
100
105


=Rs.10500
At the end of the first year he repay 35% of the sum borrowed so he repay the amount=10000×
100
35

=Rs3500
left amt=10000−3500=Rs.7000
For the second year
P
2

=Rs.7000, R=5%
A
2

=7000(1+
100
5

)
=7000×
100
105


=Rs.7350
At the end of the second year he repay 42% of the sum borrowed so he repay the amt=10000×
100
42

=Rs.4200
Left amt=7350−4200=Rs.3150
For the Third year
P
3

=Rs.3150,R=5%
A
3

=3150(1+
100
5

)
=3150×
100
105


=Rs.3307.50
Hence he pay Rs. 3307.50 at the end of the third year in order to clear the debt.

Similar questions