Cylinder radius 12height 20 iron ball is dropped in cylinder level increaae 6.75find radiusof ball
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Solution:-
Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7*12*12*6.75 = 4/3*22/7*r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
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Radius of the cylinder = 12 cm
Height of the cylinder = 6.75 cm
Let 'r' be the radius of the spherical iron ball.
Volume of the cylinder = volume of the spherical iron ball
πr²h = 4/3πr³
22/7*12*12*6.75 = 4/3*22/7*r³
3 × 12 × 12 × 6.75 = 4r³
2916 = 4r³
r³ = 2916/4
r³ = 729
r = 9 cm
So, the radius of the spherical iron ball is 9 cm.
Read more on Brainly.in - https://brainly.in/question/915751#readmore
Answered by
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We know, Volume of the cylinder will be equal to volume of iron ball and radius of the base and iron ball will be same.
so,
πr²h = 20× 4/3 πr³
cancel πr² both sides
h = 4r/3 × 20
3h = 80r
r = 3h/80
r = (3×6.75+10) / 80
r = 32.25 / 80
Radius = 0.4 cm
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