Question

In the fig., AB//CD. Find the value of x.​

Answer 1

Answer:

110°

Step-by-step explanation:

by extending the line DC and connecting it to line EA at point F, we get the transversal of AB and DC as EA.

NOW , in the first case line DF is cut by EC, forming to parts of a straight line.

FIRST angle formed on DF is = 130°

therefore, 2nd angle= 50° (supplementary angles)

now, there is a triangle formed , ECF , where 2 angles are 20°, 50° .

third angle is = 180-(20+50) [sum angle property of a triangle]

therefore, angle CFE = 110°

NOW, angle CFE and CFA are equal ( as they are corresponding angles, of two straight lines cut by a transversal, at the same side of the transversal.)

Therefore, angle x/CFA = 110°

HOPE U LIKED IT .

THANKS !!

Answer 2

Answer:

bhai sis nhi bro hu.. ......