In the fig AB II CD. Find the value of x
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angle lef = angle egh {ab||cd}
an.egh + an.mgh = 180° linear pair
an.mgh = 180- 85= 95°
an.ghm + an.mhc = 180°
an.ghm = 180-115 = 65°
in triangle MGH
ang.mgh + ang.mhg + x = 180
95 + 65 + x = 180
x = 180- 160
= 20°
HOPE HELPS
an.egh + an.mgh = 180° linear pair
an.mgh = 180- 85= 95°
an.ghm + an.mhc = 180°
an.ghm = 180-115 = 65°
in triangle MGH
ang.mgh + ang.mhg + x = 180
95 + 65 + x = 180
x = 180- 160
= 20°
HOPE HELPS
jacob2137:
thank you sneha....
wlcm
please help me out again with the question which i had posted.
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