Question

in the fig ABCD is a cyclic quadrilateral. if angle BCD=110degree and angleABD =60degree ,find the measure of angle DAE and angle ADB

Answer 1

I write it in simplest form
Given
ABCDis a cyclic quadrilateral
Angle C = 110°
Angle B = 60°
Find = angle A and D
If ABCD is a cyclic quadrilateral
Angle B +angle D = 180°
(Opposite side of the cyclic quadrilateral is equal to 180°)
60° + angle D = 180°
Angle D = 180° - 60°
Angle D = 120°
Similarly we find that
Angle C + angle A = 180°
110° + angle A = 180°
Angle A = 180° - 110°
Angle A = 70°