Question

in the fig ABCD is a square its diagonal are parallel to the axes, AC=8, The coordinate of A is 2,5. Write the coordinate of the vertices C, B, D​

Answer 1

Step-by-step explanation:

let take the square as two triangles.

triangle ABC and triangle ADC.

AC=8cm

triangle ABC and triangle ADC are right triangles.

by using Pythagoras theorum,

sin 45= 1/root 2

1/root2= AB/AC

1/root2=AB/8

AB=1/root2 ×8

therefore, AB= 4root 2

AB=BC=CD=AD=4root 2

coordinates of

D= 6root 2, 9root 2

B= 2,0

C= 6root 2, 0