Math, asked by pereira16mavis1979, 8 months ago

In the fig. AD/DB = AE/EC and angle ADE = angle ACB. Prove that ABC is an isosceles triangle.
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Answered by nitsdeblaster
8

Answer:

Step-by-step explanation:

AD/DB = AE/EC

So, DE II BC (By the converse of Thales's Theorem)

⇒ ∠ ADE = ∠ ABC   ( Corresponding angles)

But, ∠ ADE = ∠ ACB       (given)

So, ∠ ABC = ∠ ACB

⇒AC = AB       (SIDES OPPOSITE TO EQUAL ANGLES)

Hence, ABC is an isosceles triangle.

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