In the fig angle A = 40, AB=AC find x & y
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AB=AC that means ≤ABC≈≤ACB≈x(suppose) then
x+x+40°= 180°
x= 70°
y°= 180°-70°= 110°
≤C≈x° [vertically opposite angle]
therefore
x°=70°
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Answer:
ANSWER:
sum of angle of triangle=180°
=n+n+40=180
=2n=180-40
=2n=140
=n=140/2
=n=70
supplementary angle=∆ABC+Y=180°
=70+Y=180
=Y=180-70
=Y=110°
∆ACB =x=70° ( vertically oposite angle)
therefore x=70°
Y=110°
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