In the fig., BC = CA and<A = 40°, then find <ACD.
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Step-by-step explanation:
In ΔABC,
AC=BD....(Given)
∠A=40°...(Given)
Therefore,
∠B=40°....( Isosceles triangle theorem)
Thus,
∠C=100°...(Sum of all angles of a triangle is 180°)
Thus,
∠ACD=80°....(Linear pair of angles)
OR
.
.
.
You can use remote angle theorem, which states that the sum of two angles of a triangle who are far (remote) from an exterior angle of the triangle is equal to the measure of that exterior angle.
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