Math, asked by nishazoyaazmat, 2 months ago

In the Fig., find the area of quadrilateral ABCD. 17 cm 9 cm 8 cm А B​

Answers

Answered by sonaliyadvscs
1

Step-by-step explanation:

Consider Δ ABD

Using the Pythagoras theorem

AD

2

=AB

2

+BD

2

By substituting the values

17

2

=AB

2

+15

2

On further calculation

AB

2

=64

By taking out the square root

AB=

64

So we get

AB=8cm

We know that

Perimeter of quadrilateral ABCD=AB+BC+CD+AD

By substitution the values

Perimeter =8+12+9+17

By addition

Perimeter=46cm

We know that area of ΔABD=

2

1

×b×h

It can be written as:

Area of ΔABD=

2

1

×AB×BD

By substituting the values

Area of Δ ABC=

2

1

×8×15

On further calculation

Area of ΔABD=60cm

2

Consider ΔBCD

We know thatBC=12cm,CD=9cmandBD=15cm

It can be written as a=12cm,b=9cmandc=15cm

So we get

s=

2

a+b+c

s=

2

12+9+15

By division,

s=18cm

We know that

Area=

s(s−a)(s−b)(s−c)

By substituting the values

Area=

18(18−12)(18−9)(18−15

So we get

Area=

18×6×9×3

It can be written as

Area=

6×3×6×9×3

On further calculation

Area=6×3×3

By multiplication

Area=54cm

2

So the area of the shaded region=Area of ΔABD+ Area of ΔBCD

By substituting the values

Area of the quadrilateral ABCD=60+54=114cm

2

Therefore, the perimeter is 46cm and the area is 114cm

2

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SIMILAR QUESTIONS

star-struck

Draw quadrilateral ABCD with the following measurements. Also find its area.

AB = 7 cm, BC = 5 cm, AC = 6 cm, CD= 4 cm, and ∠ ACD = 45

o

.

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Draw quadrilateral ABCD with the following measurements. Find also its area.

AB = 4 cm, BC = 6 cm, CD = 5 cm, DA= 5.5 cm and AC = 7 cm.

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