In the fig. (i) given, DE is parallel to BC.
Find the value of x.
Attachments:
Answers
Answered by
0
Answer:
in triangle aec,
ced +dea = 180' ( straight line )
95 + dea =180'
180-95= dea
dea = 85'
Similar questions
Physics,
1 day ago
India Languages,
1 day ago
Social Sciences,
2 days ago
Computer Science,
8 months ago
Math,
8 months ago