In the fig. if LM II CB and LN II CD, prove that
AM
MB
=
AN
ND
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Answer: By Thales theorem or basic proportionality Theorem
IN∆ABC
LM||BC so by B.P.T
AL/AC=AM/AB-----------(1)
IN∆ADC
AL/LC=AN/AD------(2)
from equation 1 &2 L.H.S is the same so R.H.S will also same.
so
AM/AB=AN/AD
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