In the fig O is the centre of the circle. AB is a chord, OP perpendicular AB, radius = 5cm, OP=3cm. then the length AB is
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Given : O is the centre of the circle.
AB is a chord,
OP perpendicular AB,
radius = 5cm, OP=3cm.
To Find : length AB
Solution:
OP perpendicular AB,
Hence P divided AB => PA = PB = AB/2
OP = 3 cm OA = OB = radius = 5 cm
Using Pythagoras theorem
OA² = OP² + PA²
=> 5² = 3² + PA²
=> PA = 4 cm
AB = 2 * PA = 2 * 4 = 8 cm
Length of AB = 8 cm
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