In the fig., PQ=24cm, PAR=90°, PA=6cm and AR=8cm. Find QPR
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this is right angle triangle so QPR=90 degree
then,
let APR &ARP=X
SO.
90+X+X=180
2X=90
X=45
APR &ARP=45
APQ+APR =90
APQ+45 =90
APQ=90-45
APQ=45
QPR =45+45
QPR=90 degree
then,
let APR &ARP=X
SO.
90+X+X=180
2X=90
X=45
APR &ARP=45
APQ+APR =90
APQ+45 =90
APQ=90-45
APQ=45
QPR =45+45
QPR=90 degree
sarada16bng:
how do u knw dat dis is a right triangle?
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