Question

In the fig. Seg PQ perpendicular Seg RQ
Seg PQ perpendicular Seg PT
Seg TS perpendicular Seg PR
Prove that : ST X RQ = PS XPQ​

Answer 1

Answer:

There u go

Step-by-step explanation:

In ∆PQR, PR is the base and QT is the corresponding height. Also, RQ is the base and PS is the corresponding height. [Ratio of areas of two triangles is equal to the ratio of the product of their bases and corresponding heights] ∴ 1/1 = (PR × QT) /(RQ × PS) ∴ 12 × QT = RQ × PS) ∴ PR X QT = 6 x 6 ∴ QT = 36/12 ∴ QT = 3 units . . .

Answer 2

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