Question

In the figure 10.13, A = 75° and CE || AB. If ZECD = 40°, find the other two;
of the triangle ABC.
750
40°
Fig. 10.13​

Answer 1

Answer:as AB is parallel to CE

BAC=ECA=75 { alternate interior angles }

ACD=75+40=115

ACD=BAC+CBA{exterior angle}

115 =75+CBA

CBA=40

A+B+C=180

75+40+C=180

C=180+115=65

Answer 2

Answer:

Step-by-step explanation:

AEC =  75 degrees (alternate interior angles)

AEC+ECD+ACB = 180 degrees (angle of a straight line)

=> 40 +75+  ACB = 180 degrees

=> 115+ ACB = 180

=>  ACB = 180 - 115

=>  ACB = 65

now, in triangle abc,

ACB + BAC + CAB = 180 (sum of angles in a triangle)

=> 65 + 75 + CAB = 180

=> 140 + CAB = 180

=>  CAB = 180 - 140

=>  CAB = 40

hence solved hope this helps u man

first time solving problem on brainly!!!