Question

In the figure 16, lines AB and CD intersect at M. PM AB. if DMB = 20, find the angles a, b, c and d. ​

Answer 1

angle c is equal to 90 - 20=70

angle d is equal to 90

angle m is equal to 180-20=160

angle a is equal to 180-160=20

Answer 2

here is your answer

$d = 90 \\ \\ amb = 180(linear \: pair) \\ \\ d + c + 20 = 180 \\ \\ 90 + c + 20 = 180 \\ \\ c = 180 - 110 = 70 \\ \\a = 20(virticl \: oppisit \: angle \: ) \\ \\ b = 160(voa)$

thanks