Question

in the figure 6.34 PQ is parallel to SR and PQRS is a trapezium angle QPS=angle RSP=90, PS=6cm SR=19cm and PQ=11cm. calculate a)the length of QR b) the length of diagonal PR

Answer 1

Answer:

QT parallel to PS, where T lies on SR.

SPQT is a parallelogram, so QT = PS = QR.

Triangles TQR and RQT are congruent (SAS), so angle QRT = angle QTR = angle PST.

Triangles OSR and ORS are congruent (AAS), so SO = RO.