In the figure 6.39 , sides QP and RQ of ∆ PQR are produced to point S and T respectively if, angle SPR =135° and angle PQR= 110°, find angle Angle PQR.
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LP QT LP QR = 180^ (Straight angle made on line TRat point Q)
110' ± LP QR= 180"
LP QR= 180' — 110' = 70'
In AP QR LP SR = LP QR LP RQ (Exterior angle of triangle is egal to sum of two interior angles)
135'= 70' ± LP RQ
LP RQ = 135' — 70' = 65"
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