Question

In the figure 8.50. AE = BE and angle C = angle D.
Prove that AD = BC.​

Answer 1

Hey mate!!

here's your answer...

Given: in given figure AE=BE and angle C=angle D

To prove: AD=BC

solution : In ∆AEC and ∆BED

angle C= angle D (given)

AE=EB(given)

angle AEC =angle BED(v.opp.angle)

so, ∆AEC and ∆BED are congruent by AAS

then, CE=ED (c.p.c.t)_______{1}

Now adding AD both side in {1}

CE+AD=ED+AD (also AD=BE)

so,CE+BE= ED+AD

BC=AD ......(Hence proved)

$<marquee>★★Hope it will be helpful for you ☺️★★$

Answer 2

Step-by-step explanation:

HOPE IT HELPS YOU.

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