Question

In the figure A and B are the mid-points of two equal chords PQ and RS
respectively of a circle with center O . prove that triangle OAQ is congruent to triangle OBS
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Answer 1

Answer:

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Answer 2

Answer with Step-by-step explanation:

A and B are mid point of equal chords PQ and RS.

$PQ=RS$

$\frac{1}{2}PQ=\frac{1}{2}RS$

$AQ=BS$

In triangle OAQ and OBS

$OA=OB$ (Equal chords are at equal distance from center)

$OQ=OS$(Radius of circle)

$AQ=BS$

$\triangle$OAQ$\cong\triangle$OBS

Reason: SSS postulate

Hence, proved

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