Question

In the figure A, B, C and D are four points on a circle. AC amd BD intersect at a point E such that angle BEC=130° and angle ECD=20°. Find angle BAC.​

Answer 1

Answer:

BAC=∠CDE ...Angles in the segment of the circle

In ΔCDEΔCDE,

∠CEB = ∠CDE + ∠DCE∠CEB=∠CDE+∠DCE ...Exterior angles of the triangle

⇒ 130° = ∠CDE + 20°⇒130°=∠CDE+20°

⇒ ∠CDE = 110°⇒∠CDE=110°

Thus, ∠BAC = 110°∠BAC=110°

Answer 2

Here is the answer..

Hope it helped u