In the figure, a part of calender is shown. A square of 4,5,11,12 numbers is marked. Find the product of diagonal pairs.
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Answer:
48 and 55
Solution :
Given :
- A square part of a calendar is taken
- 4 , 5 , 11 , 12 are the numbers.
To find :
- Product of diagonal pairs.
The diagonal pairs are 4 and 12 , 5 and 11
4 5
11 12
⟹ 4 × 12 = 48
⟹ 5 × 11 = 55
So, the product of diagonal pairs = 48 and 55
The difference between their products is 7.
Let's See the algebra used :
x x + 1
x + 7 x + 8
( cross multiply ) ( diagonal multiply )
⟹ x ( x + 8 ) × ( x + 1 ) ( x + 7 )
⟹ x² + 8x × x² + 7x + x + 7
⟹ x² + 8x + 7
so, the 2 products are :
⟶ x² + 7x + x +7
⟶ x² + 8x + 7
The difference between them is : 7
( Refer to the attachment )
Attachments:
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