In the figure, (AB)=14cm.if the
diameter of the semicircle AM and mb are equal what is the total area of the shaded part
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4
Explanation:
Given AB=14cm,BC=AD=7cm
we know that the area of rectangle=l×b
area of the semicircle=
2
π×r
2
Here the radius of the big semicircle(r
1
)=
2
14
=7cm
the radius of the small semicircle(r
2
)=
2
7
cm
Area of shaded region = Area ABCD + 2 × area small semi-circle - area big semi-circle
=(l×b)+2⋅
2
1
πr
1
2
−
2
1
πr
2
2
=(14×7)+2×
2
1
×
7
22
×
2
7
×
2
7
−
2
1
×
7
22
×7×7
=98+38.5−77=59.5cm
2
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