Question

in the figure AB = 6 CM , AC = 5 cm , angle BAC = 90°. CD is parallel to AB find the area of triangle BAC find the area of triangle BAD​

Answer 1

Answer:

hii good question but sorry I couldn't find the answer

Answer 2

Answer:

The area of both the triangles BAC and BAD is $\bold{15cm^2}$

Step-by-step explanation:

We are given,

The base of the triangle BAC $=6cm$

Height of the triangle BAC $=5cm$

The area of a triangle:

$=\frac{1}{2}\times Base\times Height\\=\frac{1}{2}\times6\times5\\=15cm^{2}$

The base of the triangle BAD $=6cm$

Height of the triangle BAD $=5cm$

The area of a triangle:

$=\frac{1}{2}\times Base\times Height\\=\frac{1}{2}\times6\times5\\=15cm^{2}$

Therefore, the area of both the triangles BAC and BAD is $\bold{15cm^2}$.