Question

in the figure AB=AC,D is the point in the interior of ∆ABC and such <DBC=<DCB. Prove that AD bisect <BAC of ∆ABC

Answer 1

angle ABC is a icociles triangle because ab is equal to ac so angle b is equal to angle a ad is a common cord ab is equal to ac given angle cis equal to angle b icociles triangle draw a line de so dc is midium db is also a midium db is equal to dc so by sss t angleadc is cong to tringle dac so by cpct bad is equal to dac ............ hance proved

Answer 2

CRM

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