Question

In the figure, AB || CD || EF and GH|| KL.Then ZHKL is​

Answer 1

Answer:

∠145°

Step-by-step explanation:

//If i understand correctly you want angle HKL.

∠CHG = 60° ; ∠DHK = 25°

GM || LN

∠MHZ = 60° (vertically Opposite angle to ∠CHG)

G and L are parallel lines. CD and AB are parallel lines.

MKZH is a parallelogram.

∠ZHM = ∠ZKM = 60° (Opposite angles in a parallelogram are congruent)

∠HKM = 25° (Alternate Angle to ∠DHK)

∠K = ∠ZKM + ∠MKL = 180°

∠MKL = 180° - 60° = 120°

∠HKL = ∠HKM + ∠MKL = 25° + 120° = 145°

Answer 2

Answer:

The above attachement is your answer!

Hope it helps you ✌️✌️