Question

In the figure, AB= CD. Prove that BE=DE and AE=CE, where E is the point of intersection of AD and BC.​

Answer 1

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\pink{Answer:-}$

⏩ In ∆s AEB and CED, we have

angle BAE= angle DCE (Angles in the same segment)

and,

angle ABE = angle CDE (Angles in the same segment)

AB= CD

So, by ASA criterion of congruence, we obtain

∆ AEB is congruent to ∆CED

=> AE= CE and BE=DE (C.P.C.T)

✔✔✔✔✔✔

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Answer 2

Answer:

$\huge\underline\mathfrak\purple{Solution}$