Math, asked by samuelacademy1, 5 hours ago

In the figure, AB=DE, AC=CE, and C is the midpoint of BD. a) prove that AB and DE are parallel?

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Answered by rambhadrapandey21
4

Answer:

the triangles are equal  because AB=DE and AC=CE and point C is bisector of BD so CB = DC  so by SSS condition the triangles are equal .

Step-by-step explanation:

 AB and DE are perpendicular to BD so join A and C  now BD = AC

then ABCD is a rectangle because BD = AC , AB=DE, and all angles are right angle so opposite sides are parallel

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