Question

in the figure AB is a chord of a circle with center P, seg PM chord AB . IF AB =48cm , radius of the circle 25 cm , find PM​
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Answer 1

Answer:

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Answer 2

PM=7 cm

Step-by-step explanation:

Radius of circle=PB=25 cm

AB=48 cm

We know that the perpendicular drawn from center of circle  to the chord  is always bisect the chord.

Therefore, AM=MB=$\frac{1}{2}(48)=24 cm$

In triangle PMB

$PB^2=PM^2+MB^2$

Using Pythagoras theorem  

$(hypotenuse)^2=(Base)^2+(perpendicular\;side)^2$

Substitute the values

$(25)^2=(24)^2+PM^2$

$625=576+PM^2$

$PM^2=625-576$

$PM^2=49$

$PM=\sqrt{49}=7 cm$

Hence, PM=7 cm

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