Question

?In the figure, AB is a diameter of the circle, AC = 6 cm and BC = 8 cm. Find the area of the shaded region. [Use ? = 3.14]

Answer 1

in triangle ABC, angle C is 90 degree (diameter makes 90 degree with the circle)
$\: so \: by \: pyhthagoras \: theorem \\ {ac}^{2} + {cb}^{2} = {ab}^{2} \\ {6}^{2} + {8}^{2} = 36 + 64 = 100 \\ {ab}^{2} = 100 \\ ab = 10$
radius is half of diameter so radius is 5cm
area of shaded region is area of circle-area of triangle
$area = \pi {r}^{2} - \frac{1}{2} bh \\ = 3.14 \times {5}^{2} - \frac{1}{2} \times 6 \times 8 \\ = 78.5 - 24 \\ = 54.5$

therefore your answer is 54.5 sq. cm
please follow me

Answer 2

answering the image of page