Question

In the figure AB is equal to BC and angle a is equal to angle B which is equal to 90° show that CD bisects AB

Answer 1

Answer:

AB = BC(given )

ANGLE A = ANGLE B( both 90 degree)

in triangle BOC and triangle AOD

Ab= BC( GIVEN)

angle A = angle B ( botj 90 degree)

angle O = angle O ( common)

hence proved CD BISECT AB..