In the figure , ABC is a right angled triangle in which angleA is 90.Semicircles are drawn on AC,AB and BC as Diameter.Find the area of shaded region.
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Rahul099
Primary SchoolMath 5+3 pts
In the given figure ABC is a triangle right angled at A.semicircles are drawn on AB,AC and BC as diameter.find the area of shaded region
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Follow Report by Harsh1211 27.12.2016
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Crystal3007 Helping Hand
BC²=AC²+AB²
=8²+6²
=64+36
=100
BC=10cm
Area of biggest semicircle= 1/2 * 3.14 * r²
=0.5*3.14*5*5
=0.5*78.5
=39.25 cm²
Area of 2nd Largest Semicircle = 0.5*3.14*r²
=0.5*3.14*3²
=0.5*3.14*9
=14.13 cm²
Area of smallest Semicircle = 0.5*3.14*r²
=0.5*3.14*4²
=0.5*3.14*16
=25.12 cm²
Area of Triangle = 1/2 *b*h
= 0.5*6*8
=24 cm²
Area of shaded region = (24+25.12+14.13) - 39.25
= 63.25-39.25
=24 cm²
It may help you....
What is your question?
Rahul099
Primary SchoolMath 5+3 pts
In the given figure ABC is a triangle right angled at A.semicircles are drawn on AB,AC and BC as diameter.find the area of shaded region
Advertisement
Follow Report by Harsh1211 27.12.2016
Answers
Crystal3007 Helping Hand
BC²=AC²+AB²
=8²+6²
=64+36
=100
BC=10cm
Area of biggest semicircle= 1/2 * 3.14 * r²
=0.5*3.14*5*5
=0.5*78.5
=39.25 cm²
Area of 2nd Largest Semicircle = 0.5*3.14*r²
=0.5*3.14*3²
=0.5*3.14*9
=14.13 cm²
Area of smallest Semicircle = 0.5*3.14*r²
=0.5*3.14*4²
=0.5*3.14*16
=25.12 cm²
Area of Triangle = 1/2 *b*h
= 0.5*6*8
=24 cm²
Area of shaded region = (24+25.12+14.13) - 39.25
= 63.25-39.25
=24 cm²
It may help you....
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