in the figure, ABC is a right triangle right angled at C. If D is mid-point of BC, prove that AB^2 = 4AD^2-3AC^2
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AB² = BC² + AC²
⇒ AB² = 2CD² + AC²
⇒ AB² = 2(AD²-AC²) + AC²
⇒ AB² = 2AD² -2AC² + AC²
⇒ AB² = 2AD² - AC²
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-_-
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