in the figure ABC is a triangle and BC is parallel to the y axis . Ab and AC intersects the y axis qt p and q respectively
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Answer:
Step-by-step explanation:
(i) Coordinates of A(4,0)
(ii) Coordinates of A(4,0) and B(−2,3)
Length of AB=
(−2−4)
2
+(3−0)
2
=
36+9
=
45
=3
5
units.
Coordinates of A(4,0) and C(−2,−4)
Length of AC=
(−2−4)
2
+(−4−0)
2
=
36+16
=
52
=2
13
units.
(iii) Let the ratio be k:1
∴ Coordinates of P is (
m
1
+m
2
m
1
x
2
+m
2
x
1
,
m
1
+m
2
m
1
y
2
+m
2
y
1
)=(
k+1
−2k+4
,
k+1
−4k
)
Let coordinates of P is (x,y).
x=
k+1
−2k+4
0=
k+1
−2k+4
[as P lies on y-axis]
2k=4⇒k=2
Ratio =2:1
(iv) Equation of AC
Coordinates of A(4,0) and C(−2,−4)
y−0=
4+2
0+4
(x−4)
3y=2x−8
2x−3y−8=0
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