Question

In the figure, ABCD is a parallelogram. If PC:PA =1:3 and
ar(triangle BPC) = 16 cm^2 then find ar(triangle ADP)​

Answer 1

Area of ΔADP  =  48 cm²  ABCD parallelogram , If PC:PA =1:3 and

ar(ΔBPC) = 16 cm²

Step-by-step explanation:

ABCD is a parallelogram

AC is a diagonal

Diagonal of a Parallelogram divides the parallelogram into two equal area triangles

=> Area of ΔABC = Area of ΔADC

PC:PA =1:3  (P is point on AC)

=> Area of Δ BPC =  (1/4) Area of Δ ABC

=> 16 = (1/4) Area of Δ ABC

=> Area of Δ ABC  = 64 cm²

Area of ΔADC = Area of Δ ABC

=> Area of ΔADC =  64 cm²

Area of ΔADP  =  (3/4) Area of ΔADC

=> Area of ΔADP  =  (3/4) 64

=> Area of ΔADP  =  48 cm²

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