In the figure, ABCD is a parallelogram. If PC:PA =1:3 and
ar(triangle BPC) = 16 cm^2 then find ar(triangle ADP)
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Area of ΔADP = 48 cm² ABCD parallelogram , If PC:PA =1:3 and
ar(ΔBPC) = 16 cm²
Step-by-step explanation:
ABCD is a parallelogram
AC is a diagonal
Diagonal of a Parallelogram divides the parallelogram into two equal area triangles
=> Area of ΔABC = Area of ΔADC
PC:PA =1:3 (P is point on AC)
=> Area of Δ BPC = (1/4) Area of Δ ABC
=> 16 = (1/4) Area of Δ ABC
=> Area of Δ ABC = 64 cm²
Area of ΔADC = Area of Δ ABC
=> Area of ΔADC = 64 cm²
Area of ΔADP = (3/4) Area of ΔADC
=> Area of ΔADP = (3/4) 64
=> Area of ΔADP = 48 cm²
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