Question

In the figure, ABCD is a parallelogram. The diagonals AC and BD intersect at 0; and DAC =40 ° ,CAB=35°, and DOC =110°. Calculate the measure of ABO ,ADC,ACB,and CBD.​

Answer 1

Answer:

the question is wrong please check it again

Answer 2

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Step by step explanation

LAOB =L COD [vertically opposite angle]

L OAB+ LAOB + L ABO = 180°(angle sum property)

35°+110°+ L ABO= 180°

145°+ L ABO = 180°

L ABO= 180°-145° = 35°

L ABD = L BDC ( alternate angle)

L BDC = 35°

L CAB = L ACB (Opposite side of ll.gm)

L ACB = 35°

L COB + L COD = 180° ( LINEAR PAIR)

L COB + 110° =180°

L COB= 180°-110° = 70°

°•°L ADC = L ABO + L CBO (Oppostite side of ll.gm)

L ADC = 35 +35 =90°

Thus , ABO= 35°

ADC = 90°

ACB= 35°