Question

.In the figure ABCD is a parallelogram with angle b=110.find the value of x and y ​

Answer 1

Given:

ABCD is a parallelogram.

∠B = 110°

To Find:

value of x and y

Solution:

In ΔABC,

⇒ ∠A + ∠B + ∠C = 180° [ angle sum property of a triangle]

⇒ 40 + 110 + x = 180°

⇒ 150x = 180°

⇒ x = 180 - 150

⇒ x = 30°

In ΔADC,

⇒ ∠A + ∠D + ∠C = 180°

⇒ 110 + 30 + y =180°

⇒ 140 + y = 180°

⇒ y = 180 -140

⇒ y = 40°

Therefore, the value of x = 30° and y = 40°.

Answer 2

Answer:

here :- sometimes (∆ means angle)

GIVEN:- - ABCD is a parallelogram

- angle B = 110°

TO FIND:- The value of x and y

SOLUTION:- ( in easy way )

→ In ∆ABC,

∆A + ∆B + ∆C = 180°

.•. x + 110° + y = 180°

x + y = 180 - 110

x + y = 70

x +y = 70/2

x + y = 35

x = 35

y = 35

→In ∆ADC,

∆ADC = ∆ABC

.•. 110 = 110

∆A + ∆D + ∆C = 180

40 + 110 + ∆C = 180

150 + ∆C = 180

∆C = 180 - 150

∆C = 30°