Math, asked by mahendranbiju, 15 days ago

In the figure, ABCD is a rectangle. G is a point on CD. The area of

the triangle ∆ AGH is 7 square centimetres and the area of the

triangle ∆ BGH is 4 square centimetres.

a) What is the area of the triangle ∆ AGD?

b) What is the area of the triangle ∆ BGC?

c) What is the area of the triangle ∆ ABG?

d) What is the area of the rectangle ABCD?

e) What is the relation between the area of the triangle ABG

and that of the rectangle ABCD​

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Answers

Answered by shoaib61
3

Answer:

Answer

Using Pythagoras theorem in right triangle ABC, we obtain

AC

2

=AB

2

+BC

2

⇒(5+2)

2

+(2−t)

2

={(5−2)

2

+(2+2)

2

}+{(2+2)

2

+(−2−t)

2

}

⇒49+(4−4t+t

2

)=(9+16)+(16+4+4t+t

2

)

⇒t

2

−4t+53=t

2

+4t×45

⇒−8t=−8

⇒t=1

Step-by-step explanation:

hope it helps you mark as me brainlist drop thanks please

Answered by ssabeeda84
0

Answer:

a) question answer please

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