Question

In the figure, □ABCD is a rectangle with angle ADB = 60°. Find angle BAC.

Plz...Answer !!!​

Answer 1

Answer:

Construction: Join B and D. This forms a right triangle ADB.

From the figure, we can say that angle B is 50 deg [opposite angles in a cyclic quadrilateral are supplementary]

Consider triangle ACB.

Angle ACB is 90 deg [ angle in a semicircle is 90 deg]

Angle ABC is 50 deg

So, angle BAC is 40 deg [angle sum property of a triangle].

Angle BAC is 40 deg.

Answer 2

Answer:

in rectangle ABCD , angle ADB = 60degree

here we can see that DSA is a triangle

the applying angle sum property of triangle=

abgle SDA + angle SAD + angle DSA =180 degree

60 + 45 + angle DSA = 180

105 + angle DSA = 180

angle DSA =180 - 105 = 75 degree