Question

In the figure ABCD is a square with sides of length 6 units points E and F are the mid points of CD and BC respectively. If a point is selected at random from the interior of the square what is the probability that the point will be choosen from interior of the triangle AEF​

Answer 1

Answer:

ABCD is a square with sides

of length 6 units. Points E and F are

the midpoints of sides CD and BC

respectively. If a point is selected at

random from the interior of the

square

To find: Probability that the point

will be chosen from the interior of

triangle AEF

Area of square ABCD is equal to

= 6²

=36 square units

Now we have

area( Δ DEA)= 1/2× DE×AD=1/2×3×6

=9 units²

areal( ABF) = 1/2×BF×AB 1/2×6×3=9units²

area (ECF) 1/2 EC ×CF=1/2×3×3=9/2 units²

Area (AFE) =36-9-9-9/2=27/2 unit²

We know that Probability

Number of favourable event÷Total number of event

=27/2÷36

=27÷2 x 36

3/8

Hence the Probability that the point

will be chosen from the interior of

triangle AFE=3/8

Answer 2

Answer:

Step-by-step explanation: