Question

in the figure ABCD is a trapezium in which ab is equal to 9 CM BC is equal to 7 cm and b is equal to 3 cm find the area of trapezium​

Answer 1

Step-by-step explanation:

Based on the Pythagoras theorem

AL2+DL2=AD2

By substituting the values

42+DL2=52

So we get

DL2=52−42

DL2=25−16

By subtraction

DL2=9

By taking square root

DL=9

so we get

DL=3 cm

We know that, DL=MC…( Sides of Triangle with equal length of two other sides )

So we get

MC=3 cm

From the figure, we know that LM=AB=7cm

So we know that CD=DL+LM+MC

By substituting the values 

CD=3+7+3

By addition

CD=13cm

Area of Trapezium ABCD=21 ( sum of parallel sides \times distance between them )

So we get 

Area of Trapezium ABCD=21×(CD+AB)×AL

By substituting the values

Area of Trapezium ABCD=21×(13+7)×4

On further calculation 

Area of trapezium ABCD=20×2

By multiplication

Area of trapezium ABCD=40 cm2

please mark my answer as brainliest