Question

in the figure AC = AE, AB = AD and angleBAD = angleEAC. show that BC =DE. IF U LIKE MATHS THAN ANSWER THIS QUESTION​

Answer 1

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Answer 2

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Given that,

AC = AE, AB = AD and ∠BAD = ∠EAC

To show,

BC = DE

then Proof that,

∠BAD = ∠EAC (Adding ∠DAC both sides)

∠BAD + ∠DAC = ∠EAC + ∠DAC

⇒ ∠BAC = ∠EAD

In ΔABC and ΔADE,

AC = AE (Given)

∠BAC = ∠EAD

AB = AD (Given)

Therefore, ΔABC ≅  ≅ΔADE by SAS congruence condition.

BC = DE by CPCT.

Hope it helps u.