Question

in the figure AC is equal to 24 cm BC is equal to 10 cm and who is the centre of the circle find the area of shaded region

Answer 1

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Answer 2

Solution :-

Finding the diameter of the circle at first:

AC=24cm, BC= 10 cm

So, AB= √AC²+BC² = √576+100 = √676 = 26cm

Therefore, the diameter of the circle is 26cm.

So,the radius is 13cm(r).

Now,finding the area of the semi-circle AOBC:

Area of semi-circle, A=(πr^2)/2 = 265.33 cm²

Now,finding the area of the right-angled triangle,ABC:

Area= ½ × base × height = 120cm²

Therefore, area of the shaded portion= Area of semi-circle AOBC - Area of triangle ABC= 265.33-120cm²= 145.33cm²

145.33 cm²

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@GauravSaxena01