In the figure, AD = 12, BC = 8. Find AB, CD, AC and BD. (Here two circles are concentric.)
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We have AD = 12 cm BC = 8cm
Since the perpendicular from centre to the chord bisects the chord.
So,
AM = 6 cm
BM = 4 cm
So,
AB = AM - BM
=(6-4)
=2 cm
Similarly,
CD = 2 cm
Since the perpendicular from centre to the chord bisects the chord.
So,
AM = 6 cm
BM = 4 cm
So,
AB = AM - BM
=(6-4)
=2 cm
Similarly,
CD = 2 cm
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