In the figure, AD bisects ∠A and AD ⊥ BC. Show that △ADB ≅ △ADC.
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hence proved that Triangle ABD is perpendicular to triangal ADC
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Step-by-step explanation:
AD is altitude as it bisects angle A and divides both the triangles in equal parts
AD perpendicular to BC
so, we can also say that BD=BC
Angle A is equal to angle A
∆ADB~≈∆ ADC(ASA)
BD is Equal to BC (CPCT)
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